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10k^2+7k+40k+20=0
We add all the numbers together, and all the variables
10k^2+47k+20=0
a = 10; b = 47; c = +20;
Δ = b2-4ac
Δ = 472-4·10·20
Δ = 1409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{1409}}{2*10}=\frac{-47-\sqrt{1409}}{20} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{1409}}{2*10}=\frac{-47+\sqrt{1409}}{20} $
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